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1.  Not sure if anyone else is like me and cannot stand the texture used on roughly 3/4 the back of the device. However, I solved this fairly easily with a small strip of matte black vinyl cut and placed on the back of the case near the edge. For whatever reason the texture on the back of the thing gives me chills (similar to touching one of those 3D "Motion Cards", drives me nuts.), but now it's fine with the vinyl covering it without looking out of place.
2.  The only issues that I found so far is that my Swype keyboard doesnt show any traces anymore( and trace is turned on). And also. I dont know if any of you guys use the icam app but it will only work on wi-fi, wont work on 3G/4G, so I cant see my dogs when Im away from home.
3.  Originally Posted by divechief former Palm guy here, hope I don't break any rules for this comunity, I just took a tape measure and basic math to my 3D (not the precision tools I have at work) I get 3.75 X 2.125 which equals 4.22 square inches of real estate That may be the screen size in square inches, but that's not how you measure a screen. It's the diagonal distance. Here's an example:ScreenMath.com :: HDTV Plasma and LCD Screen Size Guide
4.  Originally Posted by OmahaPaul402 Geometry fail. The area of a rectangle is the same no matter what Length and Width are if the Diagonal(H) is the same. A^2+ B^2 = C^2 Understanding fail. Screen size is not area of a rectangle... it's diagonal distance.
5.  Originally Posted by tkemack The screen is not smaller. It's a different aspect ratio. sent from my OG EVO Actually, the further from square the aspect ratio is, the fewer square inches/diagonal inches you have. I thought the 4g was a bit big though, so I'm looking forward to it being about the same or smaller.
6. ## A correction.

Originally Posted by OmahaPaul402
Geometry fail. The area of a rectangle is the same no matter what Length and Width are if the Diagonal(H) is the same. A^2+ B^2 = C^2
I usually don't care, but you are absolutely incorrect. The area of a rectangle is only dependent on height and width. In your equation, the famous Pythagorean Theorem, you are correct in that the C^2 is the diagonal and is equal to A^2 + B^2. However, this is merely related to area and does not equal area.

Thought experiment. Make A = B. You have a square. If A = 1, then C = 1.41 (roughly). Now imagine a rectangle where C = 1.41 but A = .1. B would equal about 1.4. These 2 "rectangles" have the same diagonal, but one of them is about 1/7 the area.

I wouldn't have posted if you had just been nice. Now I'm late for work.

Edit: A classic problem in Pre-Calculus (or Calc 1) is to use limits to determine which A/B ratio equals the greatest area given a particular C. The ratio is 1, I believe. A square. But it's been a while.

Edit 2: Hahaha, that became less a thought experiment and more an actual math problem. Sorrry!
7.  Originally Posted by dasbigl I usually don't do care, but you are absolutely incorrect. The area of a rectangle is only dependent on height and width. In your equation, the famous Pythagorean Theorem, you are correct in that the C^2 is the diagonal and is equal to A^2 + B^2. However, this is merely related to area and does not equal area. Thought experiment. Make A = B. You have a square. If A = 1, then C = 1.41 (roughly). Now imagine a rectangle where C = 1.41 but A = .1. B would equal about 1.4. These 2 "rectangles" have the same diagonal, but one of them is about 1/7 the area. I wouldn't have posted if you had just been nice. Now I'm late for work. My brain just exploded,,, its to early for this, lol. EVO - LUTION 3D kerred likes this.
8.  Originally Posted by zmann My brain just exploded,,, its to early for this, lol. EVO - LUTION 3D +1. No maths on launch day plz!
9.  Long time Sprint user who has been following the forums for a few months in anticipation of the new Evo 3D. Believe it or not, I was using an old Palm Treo on a Sero plan. Well, I received it yesterday evening via the Premier early release and love how smooth the interface is. WiFi is super fast. It is definitely a great experience utilizing the multimedia aspect of this phone. Spiderman was pretty cool, but haven't really played with 3D yet. My first call the person on the other end said I sounded a tad hollow. Made a few other calls with no problem besides sounding hollow. I am in San Antonio and 95% of time have pretty good reception. Now in most areas when making calls, the reception goes in and out with the display on the phone corresponding by going dead then back on. Tech support had me perform a hard reset, update my profile with still no fix. They suggested to take to a Sprint repair center and I told them a new phone shouldn't be performing like this. I am pretty bummed as the other aspects of this phone are killer. Does this sound like a defective phone? Any ideas besides replacing with a new one?? Thanks everyone.
10.  Originally Posted by jimbo There is 1 indisputable fact; the text is significantly smaller when viewing everything. I believe it is not a result of the screen size nor aspect ratio. I think it is screen resolution just like when you change your computer monitor to a higher resolution everything gets smaller. This is highly disappointing to me. It's where apple got it very right... they doubled the resolution in each direction and re-scaled everything properly. I was hoping I wouldn't have to squint to read... argh. unwired likes this.
11.  Has anyone that was using the paid version of docs2go on the 4g checked to see if it transfers to the 3d? Thanks
12.  I'm having a problem with Exchange. In People, the contacts can't be viewed Last Name, First Name, no matter how I try to configure the View settings. Any suggestions?
13.  Is anyone having problems with the Watch update? Every time I go to the Green Hornet it tells me there is an update, then it sends me to the HTC Software update screen but when I check, it says I'm all up to date. Any suggestions?
14.  Originally Posted by LexInHouston Is anyone having problems with the Watch update? Every time I go to the Green Hornet it tells me there is an update, then it sends me to the HTC Software update screen but when I check, it says I'm all up to date. Any suggestions? Yeah a bunch of people are having this problem, there's a thread here: http://forum.androidcentral.com/showthread.php?t=96539 WATCH Update Pushed Sent from my PG86100 using Tapatalk LexInHouston likes this.
15.  Netflix and Xfinity are both saying they arent compatible with this device. Thoughts?
16.  As I am new to this.. (first android phone), how do I make my lexar class 10 32gb microsdhc work on this phone?
17.  [QUOTE=dasbigl;1027001]I usually don't care, but you are absolutely incorrect. The area of a rectangle is only dependent on height and width. In your equation, the famous Pythagorean Theorem, you are correct in that the C^2 is the diagonal and is equal to A^2 + B^2. However, this is merely related to area and does not equal area. Thought experiment. Make A = B. You have a square. If A = 1, then C = 1.41 (roughly). Now imagine a rectangle where C = 1.41 but A = .1. B would equal about 1.4. These 2 "rectangles" have the same diagonal, but one of them is about 1/7 the area. I wouldn't have posted if you had just been nice. Now I'm late for work. Edit: A classic problem in Pre-Calculus (or Calc 1) is to use limits to determine which A/B ratio equals the greatest area given a particular C. The ratio is 1, I believe. A square. But it's been a while. Edit 2: Hahaha, that became less a thought experiment and more an actual math problem. Sorrry![/QUOTE My Response: or "The sum of the square roots of any two sides of an isosceles triangle is equal to the square root of the remaining side." I kid...I kid...