Playing music on a second device

[VivaTerlingua]

I know how to make a group, that is not my question.

If I am playing music in one room and want to also start playing the same music in a second room, how do I tell google to do that?

 

[matty032]

Create a group in the home app. And tell it to play music on that group. I have a group called all speakers for all the GH's. That group will play music on all the GH's. Then I have one called bedroom speakers that plays audio on the master bedroom GH, and the master bath GH.

 

[m0nti13]

I think I get what you are asking because it's a frustration of mine as well. Unless someone else has a option, I haven't found a way to add a device to an already playing song. I believe you need to restart whatever you are playing with the new group. So if you are already playing "silly kids songs" playlist on one device. You have to tell it to "play silly kids songs playlist on 'all speakers' group" and it will then restart the playlist.

Anyone have a better way?

 

[matty032]

I think I get what you are asking because it's a frustration of mine as well. Unless someone else has a option, I haven't found a way to add a device to an already playing song. I believe you need to restart whatever you are playing with the new group. So if you are already playing "silly kids songs" playlist on one device. You have to tell it to "play silly kids songs playlist on 'all speakers' group" and it will then restart the playlist.

Anyone have a better way?

That's what I have to do as well.

 

[VivaTerlingua]

I think I get what you are asking because it's a frustration of mine as well. Unless someone else has a option, I haven't found a way to add a device to an already playing song. I believe you need to restart whatever you are playing with the new group. So if you are already playing "silly kids songs" playlist on one device. You have to tell it to "play silly kids songs playlist on 'all speakers' group" and it will then restart the playlist.

Anyone have a better way?

That's exactly my problem.