SImple math will tell you how many months your battery stays good if you charge it to 80%, and how many months if you charge to 100%?
Please explain. (And what are the answers?)
Some sample numbers: If the battery capcity is b, and the number of expected charge cycles is represented as c, and the percent discharged is represented as d, then the total mAh that you would expect to use in the lifetime of the phone is b*c*d.
As an example, if draining to 0%, or using 100% is expected to net in 600 cycles, then you would take b (3500 mAh) times c (600) * d (100% discharge) = about 2.1KAh or 2100 Ah or 2,100,000 mAh. That 2100 Ah would be the total expected battery life of the device, so if you were to do that every day, you could expect that in 600 days, or about 1 year and 8 to 9 months, the battery may show serious signs of degradation.
If draining to 50%, or using 50% is expected to net in 2000 cycles, then it'd be 3500 mAh times 2000 times 50% = 3.5 KAh, or 3,500,000 mAh. Assuming you were using the phone the same amount and had to do this twice per day, then you would take the 3.5 KAh divided by 4000 cycles, and would come to about 875 days, or about 2 years and 4 or 5 months, netting you 8 to 9 months of extra activity prior to seeing serious signs of degradation.
That's the simple part, but the trickier part is getting the real numbers to substitute for the expected number of cycles that correspond to each level of normal discharge. Which the numbers that @
chanchan05 quoted, c when d = 100% and c when d = 50% are a calculation from his post. The closest I was able to come to matching those numbers was c multiplying by 1.275 for every 10% (gross) increase in d. So c for d = 90% would be 765, for 80% it'd be 975, etc. The formula for that, if anyone wants it, is c = 600*1.275^((1-d)/.1).
But if you know you only charge once every other day, and it's 80%, then we would simply have to figure out the c when d = 80% and modify the time calculation to account for less frequent charges.
Here's what I get for a scale using c + 600*1.275^((1-d)/.1):
